yDO!BOOKEƒy[ƒWƒŠƒ“ƒNz bearing@@@331 / 392 10•bŒã‚ÉBOOK‚Ìƒy[ƒW‚ÉˆÚ“®‚µ‚Ü‚· 

‡A Calculating driving force F=iƒÊ1A{ƒÊ2B{ƒÊ3C{ƒÊ4D{nFs{nMs{ƒÊ1E{ƒÊ2F{ ƒÊ3G{ƒÊ4Hj~S}W Find the driving force from the use conditions using the above formula. F = driving force S = safety factor (2 in this example) ƒÊ1, ƒÊ2, ƒÊ3, ƒÊ4 = coefficient of friction of each table ƒÊ1 = ƒÊ2 = ƒÊ3 = ƒÊ4 = 0.15 A, B, C, D, E, F, G, and H = load applied to each table A = B =C =D = 150kgf E = F = G = H = 225kgf n = number of tables = 4 Fs = seal friction = 0.30kgf Ms = metal scraper friction = 1.5kgf F = (0.15~150{0.15~150{0.15~150{0.15~150{4~0.30{4~1.5{0.15~225{0.15~225{0.15~225{0.15~225) ~ 2 à 464 (}300) kgf Rising F1 = 764kgf Falling F2 = 164kgf ‡B Calculating service life N=a~K~i1/2Sj~iWa/Wij~fc/ifw~fv~fe~f.j Find the service life from the use conditions using the above formula. N = service life = required service life (300,000 cycles) a = allowable wear amount = 0.1 mm K = coefficient of friction = 5 x 106 S = stroke = 0.2 m Wa = allowable load = 450 kgf (BTF 30) Wi = applied load = 225 kgf (Value closest to the allowable load: Select the severest one among the loads found with the load Calculating formula.) fc = contact factor = 0.85 (Two singleaxis units) fv = velocity factor = 2.0 (25 m/min [0.42m/s]) fw = load factor = 1.0 (No impact load) fe = environmental factor= 3.0 (30‹C, no foreign matter) fl = lubrication factor = 1.0 (No lubrication) N = 0.1 ~ 5 ~ 106 ~ (1/2 ~ 0.2) ~ (450/225) ~ 0.85/ (1.0 ~ 2.0 ~ 3.0 ~ 1.0) @= 354,166 The required service life of 300,000 cycles is satisfied. Type Coefficient of friction ƒÊ Types except for S type 0.15 Technical Information of Slide Shifters 330 Selection Guide Product Information Plastic Bearing Multilayer Bearing Metallic Bearing Air Bearings Technical Slide Shifter Information Corporate Profi le 