 亂DO!BOOK丒儁乕僕儕儞僋亃 bearing丂丂丂331 / 392 BOOK傪傒傞 10昩屻偵BOOK偺儁乕僕偵堏摦偟傑偡 嘇 Calculating driving force F=乮兪1A亄兪2B亄兪3C亄兪4D亄nFs亄nMs亄兪1E亄兪2F亄 兪3G亄兪4H乯亊S亇W Find the driving force from the use conditions using the above formula. F = driving force S = safety factor (2 in this example) 兪1, 兪2, 兪3, 兪4 = coefficient of friction of each table 兪1 = 兪2 = 兪3 = 兪4 = 0.15 A, B, C, D, E, F, G, and H = load applied to each table A = B =C =D = 150kgf E = F = G = H = 225kgf n = number of tables = 4 Fs = seal friction = 0.30kgf Ms = metal scraper friction = 1.5kgf F = (0.15亊150亄0.15亊150亄0.15亊150亄0.15亊150亄4亊0.30亄4亊1.5亄0.15亊225亄0.15亊225亄0.15亊225亄0.15亊225) 亊 2 佮 464 (亇300) kgf Rising F1 = 764kgf Falling F2 = 164kgf 嘊 Calculating service life N=a亊K亊乮1/2S乯亊乮Wa/Wi乯亊fc/乮fw亊fv亊fe亊f.乯 Find the service life from the use conditions using the above formula. N = service life = required service life (300,000 cycles) a = allowable wear amount = 0.1 mm K = coefficient of friction = 5 x 106 S = stroke = 0.2 m Wa = allowable load = 450 kgf (BTF 30) Wi = applied load = 225 kgf (Value closest to the allowable load: Select the severest one among the loads found with the load Calculating formula.) fc = contact factor = 0.85 (Two single-axis units) fv = velocity factor = 2.0 (25 m/min [0.42m/s]) fw = load factor = 1.0 (No impact load) fe = environmental factor= 3.0 (30亱C, no foreign matter) fl = lubrication factor = 1.0 (No lubrication) N = 0.1 亊 5 亊 106 亊 (1/2 亊 0.2) 亊 (450/225) 亊 0.85/ (1.0 亊 2.0 亊 3.0 亊 1.0) 丂= 354,166 The required service life of 300,000 cycles is satisfied. Type Coefficient of friction 兪 Types except for S type 0.15 Technical Information of Slide Shifters 330 Selection Guide Product Information Plastic Bearing Multi-layer Bearing Metallic Bearing Air Bearings Technical Slide Shifter Information Corporate Profi le